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Sagot :
Answer:
1.35 A
Explanation:
Applying,
V = IR
I = V/R..................... Equation 1
I = Current, V = Voltage, R = Resistance.
But,
R = Lρ/A............... Equation 2
Where L = Length of the wire, ρ = resistivity, A = Cross-sectional area of the wire.
Sustitute equation 2 into equation 1
V = AV/Lρ............... Equation 3
From the question,
Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m
Substitute these values into equation 3
I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )
I = (2.03×10⁻⁷)/(15×10⁻⁸)
I = 1.35 A
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