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Answer:
Solution given:
2 Al + 3 H2SO4 – Al2(SO4)3 + 3H2
2mole +3mole. --- 1 mole + 3 mole
27×2g. +3×98g-------- 342,g. + 6g
we have
2 mole of Al gives. 6g of h2
5 moles of Al gives 6/2×5=15g of hydrogen
15 g is your answer