Join IDNLearn.com and start exploring the answers to your most pressing questions. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.

What mass of NaCrO2 can be obtained from the reaction of 7.40g Cr(OH)3 with 7.60g NaOH in the following reaction: CrOH3+NaOH==>NaCrO2+2H2O

Sagot :

Explanation:

7.60 g of NaOH = 7.6/40 = 0.19 moles.

Reaction is 1:1 so NaOH in excess and Cr(OH)3 is limiting reactant.

You will get maximum of 0.0718 moles of NaCrO2 which is 0.0718*107 = 7.69 g

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your go-to source for dependable answers. Thank you for visiting, and we hope to assist you again.