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Prove algebraically that the square of any number is always 1 more than a multiple of 8

Sagot :

Thebecksidn

Answer:

This is interesting but I don't think it's provable (unless it's just the square of odd numbers).

3² = 9, which is 1 more than a multiple of 8  (8)

4² = 16, which is not 1 more than a multiple of 8  (8)

5² = 25, which is 1 more than a multiple of 8  (24)

6² = 36, which is not 1 more than a multiple of 8  (32)

7² = 49, which is 1 more than a multiple of 8  (48)

8² = 64, which is not 1 more than a multiple of 8  (64)

9² = 81, which is 1 more than a multiple of 8  (80)

10² = 100, which is not 1 more than a multiple of 8  (96)

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