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calculate the mass of 0.5 moles of caco3 in grams with procedure ​

Sagot :

Answer:

50g

Explanation:

moalr mass of CaCO3= 40g/mol+ 12g/mol+(16g/mol*3)

                                   =52g/mol+48g/mol

                                   =100g/mol

1 mol= 100g

0.5mol=x

by cross multiplication,

0.5*100gmol=x mol

x=50g

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