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Answer:
1: At temperatures below 542.55 K
2: At temperatures above 660 K
Explanation:
Hello there!
In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:
1:
[tex]0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K[/tex]
It means that at temperatures lower than 542.55 K the reaction will be spontaneous.
2:
[tex]0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K[/tex]
It means that at temperatures higher than 660 K the reaction will be spontaneous.
Best regards!