Ask questions, share knowledge, and connect with a vibrant community on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.
Sagot :
x - volume of 15% saline solution. Theres is 15% x = 0,15 x saline solution
y - volume of 40% saline solution. There is 40% y = 0,4y saline solution
You want to produce 10 mililiers so x+y= 10
And this saline has to be 30%, so you've got 30 % * 10 = 0,3 * 10 = 3 ml saline. So:
0,15x + 0,4y = 3
And you've got system of equations:
[tex]\begin{cases} x+y=10 \\ 0,15x+0,4y=3\end{cases} \\ \begin{cases} x=10-y \\ 0,15x+0,4y=3\end{cases} \\ \hbox{Substitute value from first equation to second:} \\ 0,15(10-y)+0,4y=3 \\ 1,5-0,15y+0,4y=3 \\ 0,25y=1,5 \qquad /:0,25 \\ y=\frac{1,5}{0,25}=\frac{150}{25}=6 \\ \hbox{Then:} \\ x=10-y=10-6=4[/tex]
So answer:
Volume of 15% saline solution : 4 mililiters
Volume of 40% saline solution: 6 mililiters.
y - volume of 40% saline solution. There is 40% y = 0,4y saline solution
You want to produce 10 mililiers so x+y= 10
And this saline has to be 30%, so you've got 30 % * 10 = 0,3 * 10 = 3 ml saline. So:
0,15x + 0,4y = 3
And you've got system of equations:
[tex]\begin{cases} x+y=10 \\ 0,15x+0,4y=3\end{cases} \\ \begin{cases} x=10-y \\ 0,15x+0,4y=3\end{cases} \\ \hbox{Substitute value from first equation to second:} \\ 0,15(10-y)+0,4y=3 \\ 1,5-0,15y+0,4y=3 \\ 0,25y=1,5 \qquad /:0,25 \\ y=\frac{1,5}{0,25}=\frac{150}{25}=6 \\ \hbox{Then:} \\ x=10-y=10-6=4[/tex]
So answer:
Volume of 15% saline solution : 4 mililiters
Volume of 40% saline solution: 6 mililiters.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.