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Answer:
accelerating
Explanation:
If we consider(v > u) Acceleration:
final velocity(v)= 14m/s
initial velocity(u)=10m/s
time taken(t)= 2 seconds
a= [tex]\frac{(v-u)}{t} =\frac{(14-10)}{2}[/tex]=2m/s²
If we consider (v<u) Deceleration:
final velocity(v)= 3m/s
initial velocity(u)=9m/s
time taken(t)=2 seconds
a= [tex]\frac{(v-u)}{t}=\frac{(3-9)}{2}[/tex]= -3m/s²