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Answer:
The molarity of MgCl₂ in water is 0.088 mol/L.
Explanation:
The molarity of MgCl₂ can be calculated as follows:
[tex] C = \frac{\eta}{V} = \frac{m}{MV} [/tex]
Where:
C: is the molarity =?
η: is the number of moles of MgCl₂ = m/M
V: is the volume of water = 500 mL = 0.500 L
m: is the mass of MgCl₂ = 4.18 g
M: is the molar mass of MgCl₂ = 95.211 g/mol
Hence, the molarity is:
[tex] C = \frac{m}{MV} = \frac{4.18 g}{95.211 g/mol*0.500 L} = 0.088 mol/L [/tex]
Therefore, the molarity of MgCl₂ in water is 0.088 mol/L.
I hope it helps you!