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A sample of nitrogen gas was collected via water displacement. Since the nitrogen was collected via water displacement, the sample is saturated with water vapor. If the total pressure of the mixture at 2121 °C is 1.721.72 atm, what is the partial pressure of nitrogen? The vapor pressure of water at 2121 °C is 18.718.7 mm Hg

Sagot :

Answer:

Explanation:

Total pressure = partial pressure of nitrogen + partial pressure of water vapour

partial pressure of water vapour = 18.7 mm of Hg

760 mm of Hg = 1 atm

18.7 mm of Hg = 18.7 / 760 atm

= .0246 atm

Total pressure = partial pressure of nitrogen + partial pressure of water vapour

Putting in the values in atm

1.72 atm = partial pressure of nitrogen + .0246 atm

partial pressure of nitrogen = 1.72 atm - .0246 atm

= 1.6954 atm

= 1.70 atm

partial pressure of nitrogen = 1.70 atm .

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