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Answer: 4.5 moles of [tex]H_{2}[/tex] can be made from complete reaction of 3.0 moles of Al.
Explanation:
The given reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.
Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of [tex]AlCl_{3}[/tex] and [tex]\frac{9}{2}[/tex] moles of [tex]H_{2}[/tex].
The reaction equation now will be as follows.
[tex]3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}[/tex]
The moles [tex]\frac{9}{2}[/tex] can also be written as 4.5 moles.
Thus, we can conclude that 4.5 moles of [tex]H_{2}[/tex] can be made from complete reaction of 3.0 moles of Al.
4.5 moles of H2 can be made from complete reaction of 3.0 moles of Al with hydrogen chloride.
STOICHIOMETRY:
- According to this question, aluminum reacts with hydrogen chloride to form aluminum chloride and hydrogen gas as follows:
- 2Al + 6HCI → 2AlCl3 + 3H2
- Based on this equation, 2 moles of aluminum (Al) reacts to produce 3 moles of hydrogen gas.
- Hence, 3 moles of aluminum will produce (3 × 3)/2 = 4.5 moles of hydrogen gas.
- Therefore, 4.5 moles of H2 can be made from complete reaction of 3.0 moles of Al with hydrogen chloride.
Learn more about stoichiometry at: https://brainly.com/question/22288091?referrer=searchResults
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