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Sagot :
1. Do a pun-net square.
R r
r
r
2. The offspring would be Rr, rr, Rr, rr
3. 2 of them are heterozygous(Rr),which means they would be most likely rough coats
4. Two of them are homozygous for short hair (rr) which means they are going to be soft hair.
5. Your answer is
Rr, rr
R r
r
r
2. The offspring would be Rr, rr, Rr, rr
3. 2 of them are heterozygous(Rr),which means they would be most likely rough coats
4. Two of them are homozygous for short hair (rr) which means they are going to be soft hair.
5. Your answer is
Rr, rr
Answer:
Genotype of rough coat boar - Rr
Genotype of soft coat sow mate - rr
Explanation:
Rough coat boar must be heterozygous with one dominant allele (R ) and one recessive allele (r )
Genotype of rough coat boar - Rr
Genotype of soft coat sow mate – rr
Now if these two parents are crossed , the offspring produced are represented in the punnet square below –
R r
r Rr rr
r Rr rr
Thus, 50 % of the offspring’s have rough coat (Rr) and 50 % of the offspring’s have smooth coat.
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