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Monochromatic light from a distant source is incident on a slit 0.695 mm wide. On a screen 2.16 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35 mm . You may want to review (Page) . For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Single-slit diffraction. Part A Calculate the wavelength of the light.

Sagot :

Answer:

Explanation:

slit width d = .695 x 10⁻³ m

screen distance D = 2.16 m

distance of first minima x = 1.35 x 10⁻³ m

Let wave length of light used be λ

distance of first minima x = λ D / d

putting the values

1.35 x 10⁻³  = λ x 2.16  /  .695 x 10⁻³

λ = .4343 x 10⁻⁶ m

= 434.3 x 10⁻⁹ m

= 434.3 nm .

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