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Althea’s family decided to attend the yearly sailing festival in their town. This year the boat races will include both rowing and sailing craft. Althea was excited about watching the racing events, as well as participating in the activities and seeing the informational booths for children.


1. Althea saw different types of sailboats on the water. She noticed that while each sailboat had triangular sails, different types of boats had different sizes and different numbers of sails. Here are two of the sailboats she saw:

Sagot :

MrRoyalidn

Answer:

(a)

[tex]Area= 27ft^2[/tex] --- the catboat

[tex]Area = 25ft[/tex] --- the sloop

(b)

[tex]Cost = \$40.5[/tex] -- the catboat

[tex]Cost = \$37.5[/tex] --- the sloop

Step-by-step explanation:

Incomplete question (See attachment)

For the catboat, we have:

[tex]Base = 9ft\\Height = 6ft[/tex]

For the Sloop, we have:

[tex]Base = 7 + 3 = 10ft[/tex]

[tex]Height = 5ft[/tex]

Solving (a): The area of both sailboats.

Since both are triangular, we use:

[tex]Area= 0.5 * Base * Height[/tex]

For the catboat

[tex]Area= 0.5 * 9ft*6ft[/tex]

[tex]Area= 27ft^2[/tex]

For the sloop

[tex]Area = 0.5 * 10ft * 5ft[/tex]

[tex]Area = 25ft[/tex]

The catboat has the greater sail area because 27 > 25

Solving (b): Cost of sail for each.

We have the unit price to be:

[tex]Unit = \$1.50/ft^2[/tex]

So, the cost is calculated by multiplying the unit price by the total area.

So, we have:

For the catboat;

[tex]Cost = 27ft^2 * \$1.50/ft^2[/tex]

[tex]Cost = \$40.5[/tex]

For the sloop

[tex]Cost = 25ft^2 * \$1.50/ft^2[/tex]

[tex]Cost = \$37.5[/tex]

View image MrRoyal
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