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there is a bag filled with 6 blue and 5 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting 2 that are different in colour?

Sagot :

Ivycoveredwallsidn

Answer:

60/121

Step-by-step explanation:

There are two outcomes that are included in the event "2 different in color" -- either  Red followed by Blue (RB) or Blue followed by Red (BR).

Probability of RB is [tex]\frac{5}{11}\times \frac{6}{11}=\frac{30}{121}[/tex]  The denominator 11 does not change in the second fraction because you put the first marble back; still 11 marbles in the bag.

Probability of BR is [tex]\frac{6}{11} \times \frac{5}{11}=\frac{30}{121}[/tex]

Probability of RB or BR:  add the probabilities to get 60/121.

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