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Answer:
Final of of zinc is "3.25 ml" and water is "22 ml".
Explanation:
The given values are:
Mass of Zn,
= 23.21 g
Initial volume,
= 18.75 ml
Density,
= 7.140 g/cm³
Now,
The final volume of water = [tex]Initial \ volume+Volume \ of \ Z_n[/tex]
Or,
Volume of zinc will be:
= [tex]\frac{Mass \ of \ Zn}{Density \ of \ Zn}[/tex]
On substituting the values, we get
= [tex]\frac{23.21}{7.140}[/tex]
= [tex]3.25 \ cm^3[/tex]
or,
= [tex]3.25 \ ml[/tex]
hence,
Water's final volume will be:
= [tex]18.75+3.25[/tex]
= [tex]22 \ ml[/tex]
The final volume of the water and zinc is 22 cm³
mass of zinc = 23.21 grams
Initial volume of water = 18.75 cm³
density of zinc = 7.140 g / cm³
The final volume of water and zinc can be calculated as follows:
density = mass / volume
volume of zinc = mass / density
volume = 23.21 / 7.140
volume = 3.25070028011
volume of zinc = 3.25 cm³
The final volume of water and zinc = 3.25 + 18.75 = 22.0007002801
The final volume of water and zinc = 22 cm³
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