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For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halved

Sagot :

Answer:

Following are the responses to these question:

Explanation:

Since the [tex]max^{m}[/tex] is the current of ckt which depend on the reactance which   inductor that also enables the ckt and inductor resistance [tex](X_L)[/tex] for capacities

[tex]\to X_{C}=\frac{1}{W L}[/tex]

for

[tex]\to X_{L}=wL[/tex]

When [tex]w \longrightarrow 2w[/tex]

[tex]L\longrightarrow \frac{L}{2}[/tex]

then

[tex]\to X_{L}=2 w \times \frac{L}{2}=wL[/tex]

 therefore, [tex]X_{L}[/tex] remains at the same so, the maximum current remains the in same ckt.

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