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Sagot :
Answer:
false
Step-by-step explanation:
- If -1 us a solution then putting -1 in place of x will be 0
[tex] \rm \dashrightarrow \: {x}^{2} - 6x + 5 = 0 \\ \rm \dashrightarrow \: {( - 1)}^{2} - 6( - 1) + 5 = 0 \\ \rm \dashrightarrow \: 1 + 6 + 5 = 0 \\ \rm \dashrightarrow \: 7 + 5 = 0 \\ \rm \dashrightarrow \: 12 \cancel{ = }0[/tex]
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