Answered

IDNLearn.com makes it easy to get reliable answers from knowledgeable individuals. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

Four 15 Ω resistors are connected in series with a 45 V battery. What is the current in the circuit?

Sagot :

Answer:

3A

Explanation:

Resistance=R=15

Voltage=45volts

  • we know that

[tex]\boxed{\sf Current=\dfrac{Voltage}{Resistance}}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{45}{15}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{3A}[/tex]

Ritmeksidn

The current of the circuit is 0.75 amps

The first step is to write out the parameters

Four resistors of 15 in series

15+15+15+15

= 60

voltage= 45

Current= 45/60

= 0.75

Hence the current is 0.75 amps

Please see the link below for more information

https://brainly.com/question/3712069?referrer=searchResults

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.