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If there are 3.0 liters of gas at a pressure of 2.0 atm at constant temperature, what is the pressure if the volume is reduced by one half?

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Answer:

The pressure is doubled, 4.0atm

Explanation:

Based on Boyle's law, the pressure of a gas is inversely proportional to its volume at constant temperature. The equation that describes this law is:

P1V1 = P2V2

Where P is pressure and V volume at 1, initial state and 2, final state of the gas.

Computing the values of the problem:

P1 = 2.0atm

V1 = 3.0L

P2 = ?

V2 = 3.0L / 2 = 1.5L

Replacing:

2.0atm*3.0L = P2*1.5L

6.0atmL / 1.5L = P2

4.0atm = P2

The pressure is doubled, 4.0atm

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