what is the equation of the through point (-3,6) that prependicular to the line y=3x-10 in slope intercept form ?

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21-12-2014
Mathematics

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what is the equation of the through point (-3,6) that prependicular to the line y=3x-10 in slope intercept form ?

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Luanaidn Luanaidn · Answer 1 · 2014-12-21T16:30:34-05:00

Luanaidn Luanaidn

21-12-2014

[tex]y=3x-10\\\\ General\ formula:\\y=ax+b\\\\ Line\ is\ perpendicular when\ new\ a=-\frac{1}{a}\\y=-\frac{1}{3}x+b\\\\ Passes\ through\ (-3,6):\\6=-3(-\frac{1}{3})+b\\6=1+b\ \ \ | subtract\ 1\\b=5\\\\ Equation\ for\ line\ is\ y=-\frac{1}{3}+5 [/tex]

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