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Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

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Sagot :

Answer:

make x→0

[tex]p(0)=(0)^{2}-3(0)+2[/tex]

→ [tex]p(0)=0+0+2[/tex]

→[tex]p(0)=2[/tex]

[tex]------[/tex]

Replace x→-1

[tex]p(-1)=(-1) ^{2} -3 (-1)+2[/tex]

→ [tex]p(-1)=1-3+2[/tex]

→ [tex]p(-1)=0[/tex]

[tex]----------[/tex]

Now make x→2

[tex]p(2)=(2) ^{2} -3(2)+2[/tex]

→ [tex]p(2)=4-6+2[/tex]

→ [tex]p(2)=0[/tex]

[tex]Answer:-2,0,0[/tex]

[tex]-----------[/tex]

hope it helps...

have a great day!!

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