Traciearmillaidn
Answered

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solve the quadratic linear below :
6x²-x-2=0​

Sagot :

Lilethnguyenidn

Answer:

x = 3/2; x = -1/2

Step-by-step explanation:

6x² - x - 2 = 0

⇔ 6x² - 4x + 3x - 2 = 0

⇔ (6x² - 4x) + (3x - 2) = 0

⇔ 2x(3x - 2) + (3x - 2) = 0

⇔ (3x - 2)(2x + 1) = 0

⇔[tex]\left \{ {{3x - 2=0} \atop {2x + 1=0}} \right.[/tex]

⇔[tex]\left \{ {{3x=2} \atop {2x=-1}} \right.[/tex]

⇔[tex]\left \{ {{x=2/3} \atop {x=-1/2}} \right.[/tex]

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