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POSSIBLE POINT
An engine cylinder contains 250.0 mL of gas at a pressure of 1.00 atm. As the engine runs, it compresses the cylinder, reducing the volume of the
25.0 mL. What is the new pressure of the gas at this volume?

Sagot :

Answer: The new pressure of the gas at this volume is 10 atm.

Explanation:

Given: [tex]V_{1}[/tex] = 250 mL,        [tex]P_{1}[/tex] = 1.00 atm

[tex]V_{2}[/tex] = 25.0 mL,          [tex]P_{2}[/tex] = ?

According to Boyle's law, at constant temperature the pressure of an ideal gas is inversely proportional to volume.

Therefore, formula used is as follows.

[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]P_{1}V_{1} = P_{2}V_{2}\\1.00 atm \times 250.0 mL = P_{2} \times 25.0 mL\\P_{2} = 10 atm[/tex]

Thus, we can conclude that the new pressure of the gas at this volume is 10 atm.

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