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Sagot :
The question is: HELPAAAAAAA A mountain biker moves downhill if he accelerates at 3 m / s2 and takes 15 minutes (900 seconds) down, how far does he travel? HELP ME PLEASE
Answer: The distance travelled by the mountain biker is 2430 km.
Explanation:
Given: Acceleration = [tex]3 m/s^{2}[/tex]
Time = 15 minutes (900 sec)
Displacement = ?
Formula used to calculate the final velocity is as follows.
[tex]v = u + at[/tex]
where,
v = final velocity
u = initial velocity = 0 m/s (here)
t = time
a = acceleration
Substitute the values into above formula as follows.
[tex]v = u + a \times t\\v = 0 + 3 m/s^{2} \times 900 s\\= 2700 m/s[/tex]
The relation between velocity (speed) and distance is as follows.
[tex]Speed = \frac{Distance}{time}\\2700 m/s = \frac{Distance}{900 s}\\Distance = 2430000 m (1 m = 0.001)\\= 2430 km[/tex]
Thus, we can conclude that distance travelled by the mountain biker is 2430 km.
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