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Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 14. ​What percentage of people has an IQ score greater than ​114?

Sagot :

Answer:

15.87%

Step-by-step explanation:

We start with getting the z score

Mathematically , we have this as;

z-score = (x-mean)/SD

where x = 114

z-score = (114-100)/14 = 14/14 = 1

So we want to calculate the probability values that are greater than 1

We can use the standard normal distribution table

so we have P(z> 1) = 0.15866

in percentage, we multiply by 100 and that gives 15.866 which is 15.87 people