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PLEASE HELP
Mrs. Ameldo's class has 5 students with blue eyes, 7 with brown eyes, 4 with hazel eyes, and 4 with green eyes.
Two students are selected at random. Find each probability.
HINT: These events are DEPENDENT

a) Probability of selecting a green-eyed student, and then a brown-eyed student = ___
1. 11/20
2. 7/100
3. 7/95
4. 7/10

b) P(two blue) = ___
1. 1/20
2. 5/20
3. 1/19
4. 2/5
Be sure to reduce your fractions!
(Remember, once a blue-eyed student is picked, there will be ONE LESS blue-eyed student and ONE LESS student in total.)

PART 2
a) P(hazel then blue) = ___
1. 1/19
2/ 7/380
3. 1/20
4. 1/2

b) P(brown then blue) = ___
1. 7/80
2. 7/76
3. 3/5
4. 1/4

Sagot :

Pointlessstuff06idn

Answer:

please mark my answer as brainliest:

7/100, 1/19

1/20, 7/80

Step-by-step explanation:

firstly, figure out the total amount of students:

5+7+4+4=20

remember that dependant variables means you have to multiply the values

a)

figure out probability of choosing a green eyed student:

4/20

figure out probability of choosing a brown eyed student:

7/20

multiply values:

4/20 x 7/20 = 7/100

b)

probability of choosing a blue eyed student:

5/20 = 1/4

probability of choosing another blue eyed student:

4/19 (bc theres 1 less)

multiply:

1/4 x 4/19= 1/19

PART 2

a)

probability of choosing a hazel eyed student:

4/20

probability of choosing a blue eyed student:

5/20 = 1/4

multiply:

4/20 x 1/4 = 4/80= 1/20

b)

probability of choosing a brown eyed student:

7/20

probability of choosing a blue eyed student:

5/20 = 1/4

multiply:

7/20 x 1/4 = 7/80

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