Discover new information and get your questions answered with IDNLearn.com. Join our knowledgeable community and access a wealth of reliable answers to your most pressing questions.
Sagot :
Answer:
A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³
Explanation:
This exercise should select some values such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values answer the question, for this we use the static equilibrium relations.
Σ F = 0
F + B - W = 0
the expression for thrust is
B = ρ g V_liquid
A) the weight of the block is
W = m g
W = 0.250 9.8
W = 2.45 N
Let's look for the maximum push
V_body = V_liquid
B = 500 9.8 0.05³
B = 0.6125 N
we substitute
F = W - B
F = 2.45 - 0.6125
F = 1.8375 N
B) As the body is totally submerged, the volume of the liquid and the body are equal
V = l³
V = 0.05³
V = 1.25 10⁻⁴ m³
C) the volume of water displaced is equal to the volume of the body
V_liquid = 1.25 10⁻⁴ m³
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.