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Sagot :
Answer:
A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³
Explanation:
This exercise should select some values such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values answer the question, for this we use the static equilibrium relations.
Σ F = 0
F + B - W = 0
the expression for thrust is
B = ρ g V_liquid
A) the weight of the block is
W = m g
W = 0.250 9.8
W = 2.45 N
Let's look for the maximum push
V_body = V_liquid
B = 500 9.8 0.05³
B = 0.6125 N
we substitute
F = W - B
F = 2.45 - 0.6125
F = 1.8375 N
B) As the body is totally submerged, the volume of the liquid and the body are equal
V = l³
V = 0.05³
V = 1.25 10⁻⁴ m³
C) the volume of water displaced is equal to the volume of the body
V_liquid = 1.25 10⁻⁴ m³
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