Experience the convenience of getting your questions answered at IDNLearn.com. Our experts are available to provide in-depth and trustworthy answers to any questions you may have.
Sagot :
[tex]C_6H_{12}O_6 + 6 \ O_2 \to 6 \ CO_2 + 6 \ H_2O[/tex]
1 mole of glucose : 6 moles of oxygen
First calculate the number of moles of oxygen in 10 g:
[tex]M=32 \ \frac{g}{mol} \\ m=10 \ g \\ n=\frac{10 \ g}{32 \ \frac{g}{mol}}=0.3125 \ mol[/tex]
1 mole of glucose reacts with 6 moles of oxygen
x moles of glucose reacts with 0.3125 moles of oxygen
[tex]x=\frac{1 \ mol \cdot 0.3125 \ mol}{6 \ mol} = \frac{3125}{60000} \ mol= \frac{5}{96} \ mol[/tex]
Now calculate the mass of 5/96 moles of glucose.
[tex]M=180 \ \frac{g}{mol} \\ n=\frac{5}{96} \ mol \\ m=180 \ \frac{g}{mol} \cdot \frac{5}{96} \ mol=\frac{900}{96} \ g=9.375 \ g[/tex]
The maximum mass of glucose that can be burned in 10 g of oxygen is 9.375 g.
1 mole of glucose : 6 moles of oxygen
First calculate the number of moles of oxygen in 10 g:
[tex]M=32 \ \frac{g}{mol} \\ m=10 \ g \\ n=\frac{10 \ g}{32 \ \frac{g}{mol}}=0.3125 \ mol[/tex]
1 mole of glucose reacts with 6 moles of oxygen
x moles of glucose reacts with 0.3125 moles of oxygen
[tex]x=\frac{1 \ mol \cdot 0.3125 \ mol}{6 \ mol} = \frac{3125}{60000} \ mol= \frac{5}{96} \ mol[/tex]
Now calculate the mass of 5/96 moles of glucose.
[tex]M=180 \ \frac{g}{mol} \\ n=\frac{5}{96} \ mol \\ m=180 \ \frac{g}{mol} \cdot \frac{5}{96} \ mol=\frac{900}{96} \ g=9.375 \ g[/tex]
The maximum mass of glucose that can be burned in 10 g of oxygen is 9.375 g.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.