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What is the mole fraction, , of solute and the molality, (or ), for an aqueous solution that is 12.0% NaOH by mass?
Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles. Therefore 1/(55.5+1) = 0.017. Molefraction of solute in 1 m aqueous solution is 0.017.
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