Answered

Get comprehensive answers to your questions with the help of IDNLearn.com's community. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.

Consider the piecewise function. f (x) = StartLayout Enlarged left-brace first row 2 x, x less-than 1 second row negative 4, x = 1 third row x + 8, x greater-than 1 EndLayout The function has a discontinuity at x = 1. What are Limit of f (x) as x approaches 1 minus and Limit of f (x) as x approaches 1 plus? Limit of f (x) = 2 as x approaches 1 minus. Limit of f (x) = 9 as x approaches 1 plus. Limit of f (x) = 9 as x approaches 1 minus. Limit of f (x) = 2 as x approaches 1 plus. Limit of f (x) = negative 4 as x approaches 1 minus. Limit of f (x) = negative 4 as x approaches 1 plus. Limit of f (x) D N E as x approaches 1 minus. Limit of f (x) D N E as x approaches 1 plus.

Sagot :

Likeafairy221bidn

Answer:

A) 2 9

Step-by-step explanation:

got it right on edge :) good luck!

Limit of f (x) = 2 as x approaches 1 minus. Limit of f (x) = 9 as x approaches 1 plus.

The correct option is (A)

What is piecewise function?

Piecewise function is a function built from pieces of different functions over different intervals.

The given function is: f(x)= [tex]\left \{ {{2x, \;\; x < 1} \atop {-4, \;\; x=1} \right \atop {x+8, \;\; x > 1}[/tex]

As,  piecewise function is a function built from pieces of different functions over different intervals.

As per the above discussion we can say that,

Take function for limit 1 minus, as f(x)  = 2x

put x=1,

f(x)=2, exits.

Take function for limit 1 plus, as f(x)  = x+8

put x=1,

f(x)=9, exits.

As both satisfies the definition and part (A)

As well as both limit exist and are not equal.

So, Limit of f (x) = 2 as x approaches 1 minus. Limit of f (x) = 9 as x approaches 1 plus for the given f(x).

Learn more about piecewise function here:

https://brainly.com/question/12561612

#SPJ2

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.