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Answer: 39.28 in.
Step-by-step explanation:
Given
Diameter of patch [tex]d=12.5\ in.\quad \quad [r=\dfrac{12.5}{2}][/tex]
Assume patch is in the shape of the circle
The circumference of the circle is given by [tex]2\pi r[/tex]
Circumference of the patch
[tex]\Rightarrow 2\pi \times \dfrac{12.5}{2}\\\\\Rightarrow 2\times \dfrac{22}{7}\times \dfrac{12.5}{2}\\\\\Rightarrow 39.28\ in.[/tex]