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Which graph represents (x + 5)2 + (y – 2)2 ≥ 9?

Sagot :

Answer:

The answer is A on Edge or Image with a Circle what is not shaded in

Step-by-step explanation:

The graph of an inequality (x + 5)² + (y - 2)² ≥ 9 is the set if all points on the circle (x + 5)² + (y - 2)² = 3² and outside the circle.

What is an inequality?

"It is a mathematical statement of an order relationship (greater than, greater than or equal to, less than, or less than or equal to) between two algebraic expressions."

What is a graph of a function?

"It is a set of all points on the coordinate plane that follows given function."

What is equation of circle?

"The equation of circle centered at (h, k) and radius 'r' is,

(x - h)² + (y - k)² = r² "

For given question,

We have been given an inequality (x + 5)² + (y - 2)² ≥ 9

We know the equation (x + 5)² + (y - 2)² = 9 would represent the equation of circle.

Comparing equation (x + 5)² + (y - 2)² = 3² with the standard form of circle,

We have r = 3, h = -5 and k = 2

This means, an equation (x + 5)² + (y - 2)² = 3² represents a circle with center at (-5, 2) and radius 3.

The solution to an inequality (x + 5)² + (y - 2)² ≥ 9 is the set if all points on the circle (x + 5)² + (y - 2)² = 3² and outside the circle.

The graph of an inequality (x + 5)² + (y - 2)² ≥ 9 is as shown below.

Therefore, the graph of an inequality (x + 5)² + (y - 2)² ≥ 9 is the set if all points on the circle (x + 5)² + (y - 2)² = 3² and outside the circle.

Learn more about the graph of inequality here:

https://brainly.com/question/17675534

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