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Two ships leave port at the same time. One
travels at 5 km/h on a bearing of 046º. The
other travels at 9 km/h on a bearing of 127°
How far apart are the ships after 2 hours?​

Sagot :

Answer:

19.18 km

Step-by-step explanation:

The angle between  the directions is 127 - 46 = 81

Use the law of cosines.

Let d = the distance between the ships

d^2 =10^2 +18^2 - 2*10*18 cos 81

      = 100 + 324 - 360cos 81

      = 424 - 360(.156434...)

      = 367.6835

d = 19.18 km

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