Answered

IDNLearn.com is your reliable source for expert answers and community insights. Ask your questions and receive accurate, in-depth answers from our knowledgeable community members.

10. What mass of glucose, CH,208 must be dissolved in 150.0 g of water so that the mole fraction of glucose is
0.125?

Sagot :

Sebassandinidn

Answer:

[tex]m_G=214.02g[/tex]

Explanation:

Hello there!

In this case, since the mole fraction of glucose is calculated by dividing the moles of glucose by the addition of the moles of glucose and water, we first need to calculate the moles water and then solve for those of glucose in the mole fraction:

[tex]n_w=\frac{150.0g}{18.02g/mol}=8.32mol\\\\x_G=\frac{n_G}{n_G+n_w} \\\\n_G=\frac{x_Gn_W}{1-x_G} \\\\n_G=\frac{0.125*8.324}{1-0.125} \\\\n_G=1.189mol[/tex]

And finally, we multiply by the molar mass of glucose to obtain:

[tex]m_G=1.189mol*180g/mol\\\\m_G=214.02g[/tex]

Regards!

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.