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find the distance/length of segment AB is A(2.125) and B(98, 15)

Find The Distancelength Of Segment AB Is A2125 And B98 15 class=

Sagot :

Spaceidn

Answer:

146

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Coordinates (x, y)

Algebra II

  • Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Point A(2, 125)

Point B(98, 15)

Step 2: Identify

A(2, 125) → x₁ = 2, y₁ = 125

B(98, 15) → x₂ = 98, y₂ = 15

Step 3: Find distance d

  1. Substitute in coordinates [Distance Formula]:                                               [tex]\displaystyle d = \sqrt{(98-2)^2+(15-125)^2}[/tex]
  2. [√Radical] (Parenthesis) Subtract:                                                                   [tex]\displaystyle d = \sqrt{(96)^2+(-110)^2}[/tex]
  3. [√Radical] Evaluate exponents:                                                                       [tex]\displaystyle d = \sqrt{9216+12100}[/tex]
  4. [√Radical] Add:                                                                                                 [tex]\displaystyle d = \sqrt{21316}[/tex]
  5. [√Radical] Evaluate:                                                                                         [tex]\displaystyle d = 146[/tex]
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