Answered

Get expert insights and reliable answers to your questions on IDNLearn.com. Join our Q&A platform to access reliable and detailed answers from experts in various fields.

A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m
squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?

Sagot :

Answer:

F₂ = 588 N

Explanation:

Given that,

Force, F₁ = 11760 N

Area of the cylinder, A₁ = 0.25 m²

Force on small cylinder, F₂ = ?

The area of the small cylinder, A₂ = 0.0125 m²

We know that, according to Pascal's law,

[tex]P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{11760 \times0.0125 }{0.25 }\\\\F_2=588\ N[/tex]

So, the force on the small cylinder is equal to 588 N.

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.