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Calculate the temperature needed to increase 268mL of nitrogen gas at
25°C to 824mL.*

Sagot :

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Answer:

96.92 K

Explanation:

Applying,

V/T = V'/T'..................... Equation 1

Where V = Initial Volume, T = Initial Temperature, V' = Final Volume, T' = Final Temperature.

Make T the subject of the equation

T = VT'/V'................. Equation 2

From the question,

Given: V = 268 mL, V' = 824 mL, T' = 25°C = (25+273) = 298 K

Substitute these values into equation 2

T = (268×298)/824

T = 96.92 K

Hence the Initial temperature of Nitrogen gas is 96.92 K

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