Answered

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Aluminum has an alpha value of 25 x 10^-6 1/degrees C. What is the change in
length of a 4850 cm wire at 2 degrees C when the temp increase to 55 degrees
C?

Sagot :

Eduard22slyidn

Answer:

6.4 cm.

Explanation:

From the question given above, the following data were obtained:

Coefficient of linear expansion (α) = 25×10¯⁶ / °C

Original length (L) = 4850 cm

Initial temperature (T₁) = 2 °C

Final temperature (T₂) = 55 °C

Change in length (ΔL) =?

The change in the length of the wire can be obtained as follow:

α = ΔL / L(T₂ – T₁)

25×10¯⁶ = ΔL / 4850(55 – 2)

25×10¯⁶ = ΔL / 4850 × 53

25×10¯⁶ = ΔL / 257050

Cross multiply

ΔL = 25×10¯⁶ × 257050

ΔL = 6.4 cm

Therefore, the change in the length of the wire is 6.4 cm

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