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Answer:
6.4 cm.
Explanation:
From the question given above, the following data were obtained:
Coefficient of linear expansion (α) = 25×10¯⁶ / °C
Original length (L) = 4850 cm
Initial temperature (T₁) = 2 °C
Final temperature (T₂) = 55 °C
Change in length (ΔL) =?
The change in the length of the wire can be obtained as follow:
α = ΔL / L(T₂ – T₁)
25×10¯⁶ = ΔL / 4850(55 – 2)
25×10¯⁶ = ΔL / 4850 × 53
25×10¯⁶ = ΔL / 257050
Cross multiply
ΔL = 25×10¯⁶ × 257050
ΔL = 6.4 cm
Therefore, the change in the length of the wire is 6.4 cm