Step-by-step explanation:
Radius of the circle=8
We know that
[tex]\boxed{\sf Area=\pi r^2}[/tex]
[tex] \sf \rightharpoondown \: area = \frac{22}{7} \times {8}^{2} \\ \sf \rightharpoondown \: \frac{22}{7} \times 64 \\ \sf \rightharpoondown \: \frac{22 \times 64}{7} \\ \sf \rightharpoondown \: \frac{1408}{7} \\ \sf \rightharpoondown \: 201.1units {}^{2} [/tex]
[tex]\sf More\:to\:know\begin {cases}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {cases}[/tex]
