Answer: [tex]10\left(\cos90^{\circ}+i\sin90^{\circ}\right)[/tex]
Step-by-step explanation:
Given
The complex number is [tex]z_1=0+10i[/tex]
Complex number in polar form is given by
[tex]z=r\left(\cos \theta +i\sin \theta\right)[/tex]
Compare it with the given complex number
[tex]r=10[/tex] and [tex]\sin \theta=1[/tex] which implies [tex]\theta[/tex] must be [tex]90^{\circ}[/tex]
So, in the polar form, it is
[tex]z_1=10\left(\cos90^{\circ}+i\sin90^{\circ}\right)\\z_1=10e^{i\frac{\pi}{2}}[/tex]
