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If the temperature of a gas inside a flexible container with a volume of 50 liters (L) decreases from 500°C to 100°C, then new volume will be 10L.
Volume and temperature of the gas is directly proportional to each other and for this question, equation becomes,
V₁/T₁ = V₂/T₂, where
V₁ = initial volume = 50L
T₁ = initial temperature = 500°C
V₂ = final volume = ?
T₂ = final temperature = 100°C
On putting values, we get
V₂ = (50)(100) / (500) = 10L
Hence required volume of gas is 10L.
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