Answered

For all your questions, big or small, IDNLearn.com has the answers you need. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.

A right triangle has side lengths 3, 4, and 5 as shown below.
Use these lengths to find sin A, tanA, and cosA.
B
sinA =
tanA=
S
cos.A =

A Right Triangle Has Side Lengths 3 4 And 5 As Shown Below Use These Lengths To Find Sin A TanA And CosA B SinA TanA S CosA class=

Sagot :

A right triangle has side lengths 3, 4, and 5 as shown below. [tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex][tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex][tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex].

What are the trigonometric ratios?

Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.

Given;

For angle A

Base = 4

Perpendicular = 3

Hypotenuse = 5

We know that

[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}\\\cos(\theta) = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}\\\\\tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}[/tex]

So, the functions are

[tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex]

[tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex]

[tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex]

Thus, A right triangle has side lengths 3, 4, and 5 as shown below. [tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex][tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex][tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex].

Learn more about trigonometric ratios here:

https://brainly.com/question/22599614

#SPJ1

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.