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A right triangle has side lengths 3, 4, and 5 as shown below.
Use these lengths to find sin A, tanA, and cosA.
B
sinA =
tanA=
S
cos.A =

A Right Triangle Has Side Lengths 3 4 And 5 As Shown Below Use These Lengths To Find Sin A TanA And CosA B SinA TanA S CosA class=

Sagot :

A right triangle has side lengths 3, 4, and 5 as shown below. [tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex][tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex][tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex].

What are the trigonometric ratios?

Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.

Given;

For angle A

Base = 4

Perpendicular = 3

Hypotenuse = 5

We know that

[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}\\\cos(\theta) = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}\\\\\tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}[/tex]

So, the functions are

[tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex]

[tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex]

[tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex]

Thus, A right triangle has side lengths 3, 4, and 5 as shown below. [tex]\sin(A) = \dfrac{\text{3}}{\text{5}}[/tex][tex]\cos(A) = \dfrac{\text{4}}{\text{5}}[/tex][tex]\tan(A) = \dfrac{\text{3}}{\text{4}}[/tex].

Learn more about trigonometric ratios here:

https://brainly.com/question/22599614

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