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Triangle ABC has vertices located at A(1, -4), B(4, -6) and C(2, -1) on a coordinate grid. After it is reflected across the y-axis and a dilation of ½ is applied, what is the new coordinate of B? A. (4,6) B. (8,12) C. (2,3) D (-2, -3)

Sagot :

MrRoyalidn

Answer:

[tex]B' = (-2,-3)[/tex]

Step-by-step explanation:

Given

[tex]A = (1,-4)[/tex]

[tex]B = (4,-6)[/tex]

[tex]C = (2,-1)[/tex]

reflection across y

[tex]d = \frac{1}{2}[/tex]

Required

New coordinate of B

When reflected across the y-axis.

The rule is:

[tex](x,y) \to (-x,y)[/tex]

So:

[tex](4,-6) \to (-4,-6)[/tex]

Next is a dilation by 1/2

To do this, we multiply the new point by 1/2

So:

[tex]B' = (-4,-6) * \frac{1}{2}[/tex]

[tex]B' = (-4* \frac{1}{2},-6* \frac{1}{2})[/tex]

[tex]B' = (-2,-3)[/tex]

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