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the weights of ten cats in pounds are 14, 10, 11, 9, 12, 8, 8, 10, 7, and 10. what is the mean absolute deviation of the weights of the cats?

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Aveanidn

Answer:

HOW TO DO STEP BY STEP:)

Original set ={14, 10, 11, 9, 12, 8, 8, 10, 7,10}

n = 8 is the number of values in that set above

Add up the values 12+11+7+10+10+11+6+8+14+8 = 97

Divide that sum by n = 8 to get 97/8 = 12. So the mean = 12

For each value in the original set {14, 10, 11, 9, 12, 8, 8, 10, 7,10} subtract off the mean = 12. Apply the absolute value to ensure the result is positive or zero

|x - mean| = |14 - 12| = -2

|x - mean| = |10 - 12| = 2

|x - mean| = |11- 12| = 1

|x - mean| = |9 - 12| = 3

|x - mean| = |12 - 12| =0

|x - mean| = |8 - 12| = 4

|x - mean| = |8 - 12| = 4

|x - mean| = |10 - 12| =2

|x - mean| = |7 - 12| = 5

|x - mean| = |10 - 12| = 2

The set of results we get are: {-2,2,1,3,4,4,2,5,2 } -2,2,1,3,4,4,2,5,= 21, then we divide 21 that over n = 12 (21/12) to get  = 1.75

Therefore the mean absolute deviation (MAD) is 1.75

Answer:

So lol im sorry i kinds just calculated it up on the calculator wont be able to provide an explanation but it gave me 1.72 as the Mean Absolute Deviation so the answer would be 1.72 pounds

Hope this helps!

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