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Calculate the volume occupied by 4.2g of nitrogen at STP?​

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Answer:

3.36 dm³

Explanation:

STP: Means Standard temperature and pressure.

According to Avogadro's Law, it states that the molar volume of every gas is the volume occupied by one mole of that gas at stp and is equal to 22.4 dm³

From the question,

1 mole of Nitrogen gas (N₂)  occupies a volume of 22.4 dm³

But,

1 mole of nitrogen gas has a mass of 28 g

Therefore,

28 g of nitrogen gas occupies a volume of 22.4 dm³,

Then,

4.2 g will occupy a volume of X dm³

X = (22.4×4.2)/28

X = 3.36 dm³

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