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May someone assist, please...? I don't know how to do chemistry work...
1) How many mL of 5.00M CaSO4 solution must be


diluted with water to prepare 500.0 mL of 0.900M CaSO4?


2) 20.0 mL of a stock solution of NaOH is diluted with water to prepare 150.0mL of 1.50 M NaOH solution.


Calculate the Molarity of the stock NaOH solution?


3) 12.00 mL of 3.50 M NaOH solution is diluted with 88.0 mL of water.


What is the concentration of sodium hydroxide in the diluted solution?


4) 9.0 mL of 8.0 M HCl solution is diluted with water to prepare 0.50 M HCl solution. What is the final volume of this solution?

Sagot :

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Answer:

1) 90.0 mL

2) 11.25 M

3) 0.477 M

4) 144 mL

Explanation:

The main formula that will be used for all these calculations is:

                                                     C₁V₁ = C₂V₂

C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.

For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.

1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:

5.00 M · V₁ = 500.0mL · 0.900 M                        - divide by 5.00

C₁ = 90.0 mL

2) This time we're finding the initial concentration:

20.0mL · C₁ = 150.0mL · 1.50 M                          - divide by 20.0mL

C₂ = 11.25 M

3) Now we're finding the final concentration:

12.00mL · 3.50 M = 88.0mL · C₂                         - divide by 88.0mL

C₂ = 0.477 M

4) Finally, we're looking for the final volume:

9.0mL · 8.0 M = 0.50 M · V₂                                - divide by 0.50 M

V₂ = 144mL

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