Answered

IDNLearn.com makes it easy to get reliable answers from experts and enthusiasts alike. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.

A jar contains 18 apple lollipops, 7 strawberry lollipops, and 10 grape lollipops. Irvin randomly selects a lollipop, gives it to his brother, and then randomly selects another lollipop for himself.

What is the probability that Irvin selected a grape lollipop for his brother and an apple lollipop for himself?

Write your answer as a percent. Round to the nearest tenth of a percent.

Sagot :

First  choice is  "1 of 10 grape lollipops from 35 lollipops"  
The probablity is 10/35 = 2/7 
Second choice is  "1 of 18 apple lollipops from 34 lollipops"  
So probablity is 18/34 = 9/17 
Between this is  AND so you have to these probablities multiply:
P(A) = 2/7 * 9/17 = 18/119 
P(A) = 18/119 * 100% = 1800/119 %
It is approximaly 15,1 %. 
44popcorn44idn

Answer:

15.1%

Step-by-step explanation:

So we need to find the probabilities and multiple them to get our answer. Our first probability is out of 35 lollipops total how likely is it that Irvin picks a grape.

10/35

But then Irvin gets another lollipop for himself. What is the likelihood he will get a apple lollipop out of the 34 (we removed one to give to his brother).

18/34.

So our final equation is

10/35 x 18/34=0.151 (rounded)

15.1%

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.