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Question 1
ming
2.04 g of Mg react with 12.3 g of O2
2Mg + O2 --> 2Mgo
How much MgO will be formed?

Question 1 Ming 204 G Of Mg React With 123 G Of O2 2Mg O2 Gt 2Mgo How Much MgO Will Be Formed class=

Sagot :

Elliecn0313idn

Answer:

Explanation:

The mole ratios of Mg to O2 to MgO in this question is 2:1:2, as seen from the balanced equation. However, since different elements have different masses, we cannot use the mole ratios for the grams of Mg and O2. Instead, we need to convert the grams of Mg and O2 to moles.

To convert the grams of Mg and O2 to moles, we first need to find their molar masses. The molar mass is essentially the atomic masses of all the elements within the molecule.

Magnesium has an atomic mass of approximately 24.305 u.  

Mg molar mass = 24.305 g/mol

Oxygen has an atomic mass of approximately 15.999 u.

O2 molar mass = 2*15.999 = 31.998 g/mol

We multiply by 2 here, because there are two atoms of oxygen per molecule of O2.

Now, to convert from grams to moles, we simply need to divide the substance's mass by the molar mass.

Mg: 2.04 g / (24.305 g/mol) = 49.5822 mol

O2: 12.3 g / (31.998 g/mol) = 0.384 mol

Since our values have been expressed in moles now, we can utilize the mole ratios. Looking at the mole ratio, for every 2 moles of Mg, there are 2 moles of MgO. Therefore, moles of Mg is equal to moles of MgO. That means there will be 49.5822 moles of MgO.

Now that we have the number of moles of MgO, we need to convert it back to grams. Once again, we need the molar mass of MgO.

MgO molar mass = 24.305 + 15.999 = 40.304 g/mol

To find the grams of MgO, we multiply the number of moles by its molar mass.

49.5822 * 40.304 = 1998.360989 grams --> 1998 grams

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