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Sagot :
Answer: [tex]\dfrac{729}{4}\ in.^2[/tex]
Step-by-step explanation:
Given
length of each patch is [tex]2\ \frac{1}{4}[/tex] in.
The size of the quilt is [tex]6\times 6[/tex] array i.e. there are [tex]6^2[/tex] patch available
The area of each patch is
[tex]\Rightarrow \dfrac{9}{4}\times \dfrac{9}{4}\\\\\Rightarrow \dfrac{81}{16}\ in.^2[/tex]
The area of the whole quilt is
[tex]\Rightarrow 36\times \dfrac{81}{16}\\\\\Rightarrow \dfrac{729}{4}\ in.^2[/tex]
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